mysql - Converting SQL Table ID into another field in PHP -

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so i'm trying following work;

//search userpets table user owns $query = "select * userpets owner = '$username'"; $result = mysqli_query($conn, $query); $row = mysqli_fetch_assoc($result);  $userspets = $row['petid'];  //search pets table list of pet names , details $query = "select * pets"; $result = mysqli_query($conn, $query); $row = mysqli_fetch_assoc($result);  $petid = $row['id'] $petname = $row['petname']; $petimg = $row['petimg']  //turn pet id pet name , image  echo "pets: ".$userspets;

essentially i'm trying this; 'userpets' table contains 'owned' pets , players username displayed. want grab pets owned user , compare petid 'pets' table. want take pet's name , image table , 'echo' onto page.

getting ids fine, don't know how make convert id's names.

table structure

you can use join of mysql or foreach of php

this example using php foreach

$query = "select * userpets owner = '".$username."'"; $result = mysqli_query($conn, $query);  $petid = array(); // store petid of user  $rows = mysqli_fetch_all($result,mysqli_assoc);  foreach($rows $row) {     $petid[] = $row['petid']; }  $query = "select * pets id in (".implode(",",$petid).")";  // implode convert array string delimete // example array(0=>35, 1=>36, 2=>48) convert "35,36,48" // , above query should : select * pets id in (35,36,48)  $result = mysqli_query($conn, $query); $pets = mysqli_fetch_assoc($result);  // dump  echo "<pre>"; var_dump($pets); echo "</pre>"; die;

using mysql join

<?php   $query = "select pet.id, pet.petname, pet.petimg, up.owner pets pet left join userpets on pet.id = up.pet_id up.owner = '".$username."'";

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