python - using beautifulsoup to get second and third child in BeautifuSoup -

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this question has answer here:

i have table similar below:

<table>     <thead>         <tr>             <th></th>             <th></th>             <th></th>             <th></th>         <tr>     </thead>     <tbody>         <tr>             <td></td>             <td></td>             <td></td>         </tr>         <tr>             <td></td>             <td></td>             <td></td>         </tr>         <tr>             <td></td>             <td></td>             <td></td>         </tr>         <tr>             <td></td>             <td></td>             <td></td>         </tr>         <tr>             <td></td>             <td></td>             <td></td>         </tr>     </tbody> </table>

i need second , third of each row. using beautifulsoup in python 3.5

right now, i'm doing:

table = soup.find('table', attrs={'id': 'field'})         tbody = table.find('tbody')         records = tbody.find_all('tr')         record = records.find_all('td')         field in records:             print (record[2].text)

i receiving error: 

traceback (most recent call last):   file "c:/users/arcee/pycharmprojects/scraper/main.py", line 33, in <module>     record = records.find_all('td') attributeerror: 'resultset' object has no attribute 'find_all'

is there easier way second , third td elements?

thanks

you're getting error because of these lines:

records = tbody.find_all('tr') record = records.find_all('td')

find_all returns list (resultset) of occurrences of searched tag. resultset doesn't have find_all attribute - each individual member of does. so, doing..

records = tbody.find_all('tr') record in records:     print(record.find_all('td'))

will make code run.


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