regex - How do you match character OR end of string in a golang regexp? -

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i having trouble working out (in golang), within regular expression, how match character, separator, or end of string. following want:

url := "test20160101" if i, _ := regexp.matchstring("[-a-za-z/]20[012]\\d[01]\\d[0123]\\d[-a-za-z/]", url); == true {     t := regexp.mustcompile("[-a-za-z/](20[012]\\d[01]\\d[0123]\\d)[-a-za-z/]").findstringsubmatch(url)[1]     fmt.println("match: ", t) }

https://play.golang.org/p/ewz_diovbl

but want match following:

url := "test-20160101-" url := "/20160101/page.html"

i notice there \z in the golang documentation doesn't work, @ least when put inside [-a-za-z/] i.e. [-a-za-z\\z/]

i interested , played around fun. maybe this: https://play.golang.org/p/grvnhtww0g

package main  import (     "fmt"     "regexp" )  func main() {      // want match "test-20160101", "/20160101/" , "test-20160101"      re := regexp.mustcompile(`[-a-za-z/](20[012]\d[01]\d[0123]\d)([-a-za-z/]|\z)`)     urls := []string{         "test-20160101",         "/20160101/page.html",         "test20160101",         "nomatch",         "test19990101",     }      _, url := range urls {         t := re.findstringsubmatch(url)         if len(t) > 2 {             fmt.println("match", url, "=", t[1])         }     } }

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