Python equivalent of Matlab's hist3 -

for i=1:n     centersx(:,i)=linspace(min(xdata)+dx/2,max(xdata)-dx/2,nbins)';     centersy(:,i)=linspace(min(ydata)+dy/2,max(phase)-dy/2,nbins)';      centers = {centersx(:,i),centersy(:,i)};     h(:,:,i) = hist3([xdata ydata],centers); end 

in each iteration, construct centersx , centersy linspace function. store them in 2x1 cell array called centers. h nbins x nbins x n struct. in each iteration fill nbins x nbins slice of h data hist3.

i'm looking python equivalent. i'm having trouble passing arguments numpy.histogram2d:

h[:,:,i] = numpy.histogram2d(xdata,ydata,centers) 

i following error:

traceback (most recent call last):   line 714, in histogramdd     n, d = sample.shape attributeerror: 'list' object has no attribute 'shape'  during handling of above exception, exception occurred:  traceback (most recent call last):   line 36, in <module>     h[:,:,i] = numpy.histogram2d(xdata, ydata, centers)   line 714, in histogram2d     hist, edges = histogramdd([x, y], bins, range, normed, weights)   line 718, in histogramdd     n, d = sample.shape valueerror: many values unpack (expected 2) 

since python doesn't have cell arrays, changed centers array of arrays centers[0] = centersx , centers[1] = centersy. need change such that assuming data same between matlab , python outputs match?

edit: have tried h[:,:,i] = numpy.histogram2d(xdata,ydata, bins=(centersx,centersy)) cutout combining step centers no luck.