python, list compare, ValueError: The truth value of an array with more than one element is ambiguous. Use a.any() or a.all() -

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here python code:

def ava_check(nodes_group,child_list):     ava_list=nodes_group[:]      if nodes_group[1] in child_list:         return none     else:         in nodes_group:             if in child_list:                 ava_list.remove(a)                 ava_list.remove(nodes_group[nodes_group.index(a)-1])             else:                 pass

the nodes_group list [0.0, (0, 3), 0.0, (0, 2), 0.0, (1, 3)]. child_list list [(0, 1)].

but when run code, there error: valueerror: truth value of array more 1 element ambiguous. use a.any() or a.all() happened in line if in child_list:. have no idea problem here. tried search, said numpy. didn't use numpy here, 2 inout arguments list tuples.

could me problem?

thanks much.

update: everyone's solution. data (not tuples) in list nodes_group numpy array. store data in new list. checked data type of element in new list using type(), , found type numpy.float64, explains why have error. write loop change type of element in list numpy.float64 int using int(). problem solved. know whether better solution or more pythonic way? thanks.

one (or more) of values in nodes_group list numpy array, not float or tuple show in example data. can't use test a in some_list if a array, because array's == operator doesn't return bool value, rather boolean array. boolean array raises exception see when python tries covert single bool.


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