getopt - Running a bash script with mandatory arguments -

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i want bash script working when type

bash.sh --subj directoryname --input filename --all

--subj, --input, , --all required make script work, , --all argument not require input.

if either --subj or --input missing, want following message printed:

please provide both directory name , file name.

if --all argument missing, want print:

please use --all option.

i fix script github using optparse. 

source optparse.bash optparse.define short=s long=subj desc="subject name" variable=subj optparse.define short=i long=input desc="the file process" variable=input optparse.define short=a long=all desc="all option" variable=all value=true default=false  source $(optparse.build) if [ "$subj" == "" ];    echo "error: please provide directory name"    exit 1 fi  if [ "$input" == "" ];    echo "error: please provide input"    exit 1 fi  if [ "$all" == "" ];    echo "error: please use option"    exit 1 fi

https://github.com/nk412/optparse/blob/master/sample_head.sh

using code, please provide directory name when missed --subj or -input. when miss all, not error. know why that?

from doc:

flags defined in same way, parameter value assigned variable.

optparse.define short=v long=verbose desc="set flag verbose mode" variable=verbose_mode value=true default=false

this want, flags options don't require arguments.


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