arrays - Find indices of blocks of 0s that are continuous -

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this question has answer here:

i have vector , want find indices of blocks of 0s continuous @ least 3 times. 

y = [1 1 1 0 1 1 0 0 0 1 1 1 0 1 0 1 0 0 1 0 0 0 0 1 1];

so in case, blocks should [0 0 0] 7-9 , [0 0 0 0] 20-23. output should give me indices, [7, 9] , [20,23], or better, change these blocks of 0s single nan become:

[1 1 1 0 1 1 nan 1 1 1 0 1 0 1 0 0 1 nan 1 1]

thanks!

what can is:

  1. pad vector 1 on each side.
  2. use find , diff find vector changes 1 0 (diff = -1)
  3. use find , diff find vector changes 0 1 (diff = 1)
  4. find duration of each interval subtracting values in 3 values in 2 (and add 1)
  5. create logical vector true duration >= 3, , use vector find start indices (from values found in point 2).
  6. set value of each of start indices nan
  7. set value of start indices + 1 : end indices [].

and you're set go!

it took lot more time writing explanation took write code. it's quite nice exercise learn basic matlab i'll leave you. luck!


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